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float Icc_LPRUN(void) { float Current; uint16_t MeasurINT; /* Get Icc current value in Low power mode*/ MeasurINT = ADC_Icc_Test(MCU_LP_RUN); /* Substract operational amplifier bias current from value*/ if ( MeasurINT > Bias_Current ) MeasurINT -= Bias_Current; /* Convert value in uA*/ Current = MeasurINT * Vdd_appli()/ADC_CONV; Current *= 20L; /* Display mesured value */ display_MuAmp((uint32_t)Current); /* Return value in uA*/ return(Current); } 问: Current *= 20L; //这个为什么是乘20? FAQ上网友的问题,请朋友们帮忙解答一下。 https://www.stmcu.org.cn/faq/index/detail/id-70585 |
| 没玩过,,,,,,,, |
| 帮顶 |
| MAX9938FE的增益是50. |
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