C语言问题：us_view的值是怎么得到9479的？？？
#include<stdio.h>#include<windows.h>
#include<string.h>
#define SOLID 0
#define DOTTED 1
#define DASHED 2
#define BLUE 4
#define GREEN 2
#define RED 1
#define BLACK 0
#define YELLOW (RED | GREEN)
#define MAGENTA (RED | BLUE)
#define CYAN (GREEN | BLUE)
#define WHITE (RED | GREEN | BLUE)
#define OPAQUE 0x1
#define FILL_BLUE 0x8
#define FILL_GREEN 0x4
#define FILL_RED 0x2
#define FILL_MASK 0xe
#define BORDER 0x100
#define BODRE_BLUE 0x800
#define BODER_GREEN 0x400
#define BODER_RED 0x200
#define BODER_MASK 0xe00
#define B_SOLID 0
#define B_DOTTED 0x1000
#define B_DASHED 0x2000
#define STYLE_MASK 0x3000
const char *colors[] =
{"black","red","green","yellow","blue","magenta","cyan","white"};
struct box_props
{
int opaque :1;
unsigned int fill_color :3;
unsigned int :4;
int show_border :1;
unsigned int border_color :3;
unsigned int border_style :2;
unsigned int :2;
};
union views
{
struct box_props st_view;
unsigned short us_view;
};
void show_settings(unsigned short);
int main(void)
{
union views box = {{1,YELLOW,1,GREEN,DASHED}};
char bin_str;
printf("\nbox settints using unsigned int view:\n");
show_settings(box.us_view);
system("pause");
return 0;
}
void show_settings(unsigned short us)
{
printf("box is %s.\n",(us & OPAQUE) == OPAQUE ? "opaque" : "transparent");
printf("the fill color is %s.\n",colors[(us >> 1) & 07]);
printf("border %s.\n",(us & BORDER) == BORDER ? "shown" : "not shown");
printf("the border style is");
switch (us & STYLE_MASK)
{
case B_SOLID :printf("solid.\n");
break;
case B_DOTTED :printf("dotted.\n");
break;
case B_DASHED :printf("dashed.\n");
break;
default :printf("unknown type.\n");
}
printf("the border color is %s.\n",colors[(us >> 9) & 07]);
}
编译软件：VS2010
电脑系统：win10家庭版
问题：
此代码是C Primer Plus书中第15章的（程序清单15.4 dualview.c）
请各位帮忙看看这个us_view = 9479是怎么求到的？？
本人C基础还比较差，谢谢各位啦！
看一下 us_view 地址，编译器分配给它的，与上面哪个成员地址对其。 另外不同编译器定义会有不同，这里只要讨论与STM32相关的应用。
页:
[1]