问题：双重 ADC 多通道规则同步下，DMA 传送结果到数组出错
本帖最后由 sun0727 于 2017-9-13 03:15 编辑设想的是这样的
ADC1 作为 MasterADC 控制如下 5 路, 结果依次付给 数组 的 0-4 低16位：
ADC1_IN1 -------> ADCConvertedData 低16位
ADC1_IN2 -------> ADCConvertedData 低16位
ADC1_IN3 ------>ADCConvertedData 低16位
ADC1_IN4 ------> ADCConvertedData 低16位
ADC1_IN12-----> ADCConvertedData 低16位
ADC2 作为 SlaveADC 控制如下 3 路, 结果依次付给 数组 的 0-2 的高16位：
ADC2_IN1-------> ADCConvertedData 高16位
ADC2_IN3-------> ADCConvertedData 高16位
ADC2_IN4-------> ADCConvertedData 高16位
但是经过我自己的编写，发现 ADC1 能扫描，但是 ADC2 结果在数组中的位置并不固定，原因是因为 ADC2 下的通道是 3 个 ，ADC1 的通道是 5 个 数量不对称 请问程序如何修改
以下是我的部分配置
DMA 配置
DMA_HandleTypeDefADC1_DMA_Handle;
void ADC1_DMA_Init(ADC_HandleTypeDef* hadc)
{
ADC1_DMA_Handle.Instance = DMA1_Channel1;
ADC1_DMA_Handle.Init.Direction = DMA_PERIPH_TO_MEMORY;
ADC1_DMA_Handle.Init.PeriphInc = DMA_PINC_DISABLE;
ADC1_DMA_Handle.Init.MemInc = DMA_MINC_ENABLE;
ADC1_DMA_Handle.Init.PeriphDataAlignment = DMA_PDATAALIGN_WORD;
ADC1_DMA_Handle.Init.MemDataAlignment = DMA_MDATAALIGN_WORD;
ADC1_DMA_Handle.Init.Mode = DMA_CIRCULAR;
ADC1_DMA_Handle.Init.Priority = DMA_PRIORITY_HIGH;
//HAL_DMA_DeInit(&ADC1_DMA_Handle);
HAL_DMA_Init(&ADC1_DMA_Handle);
__HAL_LINKDMA(hadc,DMA_Handle,ADC1_DMA_Handle);
HAL_NVIC_SetPriority(DMA1_Channel1_IRQn, 1, 0);
HAL_NVIC_EnableIRQ(DMA1_Channel1_IRQn);
}
多通道规则同步的配置
void ADC_Multimode_Config(void)
{
ADC_Multimode.Mode = ADC_DUALMODE_REGSIMULT;
ADC_Multimode.DMAAccessMode = ADC_DMAACCESSMODE_12_10_BITS;
ADC_Multimode.TwoSamplingDelay = ADC_TWOSAMPLINGDELAY_4CYCLES;
HAL_ADCEx_MultiModeConfigChannel(&ADC1_Handle, &ADC_Multimode);
}ADC1 的初始化
void ADC1_Input_Init(void)
{
ADC1_Handle.Instance = ADC1;
ADC1_Handle.Init.ClockPrescaler = ADC_CLOCK_SYNC_PCLK_DIV2; /* Synchronous clock mode, input ADC clock divided by 2*/
ADC1_Handle.Init.Resolution = ADC_RESOLUTION_12B; /* 12-bit resolution for converted data */
ADC1_Handle.Init.DataAlign = ADC_DATAALIGN_RIGHT; /* Right-alignment for converted data */
ADC1_Handle.Init.ScanConvMode = ADC_SCAN_ENABLE; /* Sequencer disabled (ADC conversion on only 1 channel: channel set on rank 1) */
ADC1_Handle.Init.EOCSelection = ADC_EOC_SINGLE_CONV; /* EOC flag picked-up to indicate conversion end */
ADC1_Handle.Init.LowPowerAutoWait = DISABLE;
ADC1_Handle.Init.ContinuousConvMode = ENABLE;
ADC1_Handle.Init.NbrOfConversion = 5;
ADC1_Handle.Init.DiscontinuousConvMode = DISABLE;
ADC1_Handle.Init.ExternalTrigConv = ADC_SOFTWARE_START; /
ADC1_Handle.Init.ExternalTrigConvEdge= ADC_EXTERNALTRIGCONVEDGE_NONE; /
ADC1_Handle.Init.DMAContinuousRequests = ENABLE; /* ADC DMA continuous request to match with DMA circular mode */
ADC1_Handle.Init.Overrun = ADC_OVR_DATA_OVERWRITTEN;
HAL_ADC_Init(&ADC1_Handle);
}ADC1 Channel 配置
void ADC1_Channel_Config(void)
{
//common config for channel
ADC1_sConfig.SamplingTime = ADC_SAMPLETIME_19CYCLES_5; /* Sampling time (number of clock cycles unit) */
ADC1_sConfig.SingleDiff = ADC_SINGLE_ENDED; /* Single-ended input channel */
ADC1_sConfig.OffsetNumber = ADC_OFFSET_NONE; /* No offset subtraction */
ADC1_sConfig.Offset = 0;
ADC1_sConfig.Channel = ADC_CHANNEL_1; /* Sampled channel number */
ADC1_sConfig.Rank = ADC_REGULAR_RANK_1; /* Rank of sampled channel number ADCx_CHANNEL */
HAL_ADC_ConfigChannel(&ADC1_Handle, &ADC1_sConfig);
ADC1_sConfig.Channel = ADC_CHANNEL_2;
ADC1_sConfig.Rank = ADC_REGULAR_RANK_2;
HAL_ADC_ConfigChannel(&ADC1_Handle, &ADC1_sConfig);
ADC1_sConfig.Channel = ADC_CHANNEL_3;
ADC1_sConfig.Rank = ADC_REGULAR_RANK_3;
HAL_ADC_ConfigChannel(&ADC1_Handle, &ADC1_sConfig);
ADC1_sConfig.Channel = ADC_CHANNEL_4;
ADC1_sConfig.Rank = ADC_REGULAR_RANK_4;
HAL_ADC_ConfigChannel(&ADC1_Handle, &ADC1_sConfig);
ADC1_sConfig.Channel = ADC_CHANNEL_12;
ADC1_sConfig.Rank = ADC_REGULAR_RANK_5;
HAL_ADC_ConfigChannel(&ADC1_Handle, &ADC1_sConfig);
}ADC2 的初始化 和Channel 配置
void ADC2_Input_Init(void)
{
ADC2_Handle.Instance = ADC2;
//HAL_ADC_DeInit(& ADC2_Handle);
//HAL_ADCEx_Calibration_Start(&ADC2_Handle, ADC_SINGLE_ENDED);
ADC2_Handle.Init.ClockPrescaler = ADC_CLOCK_SYNC_PCLK_DIV2; /* Synchronous clock mode, input ADC clock divided by 2*/
ADC2_Handle.Init.Resolution = ADC_RESOLUTION_12B; /* 12-bit resolution for converted data */
ADC2_Handle.Init.DataAlign = ADC_DATAALIGN_RIGHT; /* Right-alignment for converted data */
ADC2_Handle.Init.ScanConvMode = ADC_SCAN_ENABLE; /* Sequencer disabled (ADC conversion on only 1 channel: channel set on rank 1) */
ADC2_Handle.Init.EOCSelection = ADC_EOC_SINGLE_CONV; /* EOC flag picked-up to indicate conversion end */
ADC2_Handle.Init.LowPowerAutoWait = DISABLE; /* Auto-delayed conversion feature disabled */
ADC2_Handle.Init.ContinuousConvMode = ENABLE; /* Continuous mode enabled (automatic conversion restart after each conversion) */
ADC2_Handle.Init.NbrOfConversion = 3; /* Parameter discarded because sequencer is disabled */
ADC2_Handle.Init.DiscontinuousConvMode = DISABLE; /* Parameter discarded because sequencer is disabled */
ADC2_Handle.Init.NbrOfDiscConversion = 1; /* Parameter discarded because sequencer is disabled */
//ADC2_Handle.Init.ExternalTrigConv = ADC_SOFTWARE_START; /* Software start to trig the 1st conversion manually, without external event */
//ADC2_Handle.Init.ExternalTrigConvEdge= ADC_EXTERNALTRIGCONVEDGE_NONE; /* Parameter discarded because software trigger chosen */
ADC2_Handle.Init.DMAContinuousRequests = ENABLE; /* ADC DMA continuous request to match with DMA circular mode */
ADC2_Handle.Init.Overrun = ADC_OVR_DATA_OVERWRITTEN; /* DR register is overwritten with the last conversion result in case of overrun */
HAL_ADC_Init(&ADC2_Handle);
}
//--------------------Configure the ADC2 Channel-----------------------------------
void ADC2_Channel_Config(void)
{
//common config for channel
ADC2_sConfig.SamplingTime = ADC_SAMPLETIME_19CYCLES_5; /* Sampling time (number of clock cycles unit) */
ADC2_sConfig.SingleDiff = ADC_SINGLE_ENDED; /* Single-ended input channel */
ADC2_sConfig.OffsetNumber = ADC_OFFSET_NONE; /* No offset subtraction */
ADC2_sConfig.Offset = 0;
ADC2_sConfig.Channel = ADC_CHANNEL_1; /* Sampled channel number */
ADC2_sConfig.Rank = ADC_REGULAR_RANK_1; /* Rank of sampled channel number ADCx_CHANNEL */
HAL_ADC_ConfigChannel(&ADC2_Handle, &ADC2_sConfig);
ADC2_sConfig.Channel = ADC_CHANNEL_3;
ADC2_sConfig.Rank = ADC_REGULAR_RANK_2;
HAL_ADC_ConfigChannel(&ADC2_Handle, &ADC2_sConfig);
ADC2_sConfig.Channel = ADC_CHANNEL_4;
ADC2_sConfig.Rank = ADC_REGULAR_RANK_3;
ADC2_sConfig.SamplingTime = ADC_SAMPLETIME_1CYCLE_5;
HAL_ADC_ConfigChannel(&ADC2_Handle, &ADC2_sConfig);
}
函数的调用
#define ADC_CONVERTED_DATA_BUFFER_SIZE ((uint32_t)5) /* Size of array aADCxConvertedData[] */
uint32_t aADCxConvertedData;
//------------------------------Start ADC in Dualmode and DMA --------------------------------------
void ADC_DMA_Dualmode_Start(void)
{
ADC1_Input_Init();
ADC_Multimode_Config();
ADC1_Channel_Config();
ADC2_Input_Init();
ADC2_Channel_Config();
//
//
HAL_ADC_Start(&ADC2_Handle);
HAL_ADCEx_MultiModeStart_DMA(&ADC1_Handle,(uint32_t *)aADCxConvertedData,ADC_CONVERTED_DATA_BUFFER_SIZE);
}
你数据是分：高16位、低16位，
而接收到的数据只有12位，
是不是应该把高16位的数据，右移4位，
并把右移出来的部分，填充到低16位的高４位中呢？
写的有点拗口，希望能明白我在说什么。;P 本帖最后由 sun0727 于 2017-9-13 03:16 编辑
求大神指点这种 数量非对称的 双重 ADC STM32的ADC转换分辨率只有12位，楼主为何要把它拆成2个16位来读取？ 前一段时间使用双重同时采样，我的设置中，ADC1和ADC2的转换通道是一样多，我想楼主如果ADC通道有多余，也可以考虑在ADC2中增加几个多余通道。另外，DMA的字长一定要设置成32位。附件是我工程。 弄成同样通道数吧，两路ADC扫描频率相同，采样率相同，只是内存得多开一点。 看代码好像是采用中断调用DMA，既然如此各个通道带参数独立调用DMA，存储到自己定义的数组中，回调数据时，按照规定读取或输出，这样就没有需要多用存储的要求了。想想是吗？ 搞FOC的吧 楼主你这个问题解决了吗？能不能帮我看一下我的工程，跟你的设置的一样，只不过我的是对称adc转换的，但是在转换时发现各通道的数据都是不对，这该怎么办？是我配置错误了吗？ 文件有点大，不好意思
页:
[1]