anywill 发表于 2016-10-30 21:55:46

ARM®mbed OS入门开发 诺基亚5110 SPI显示



【STM32 Mbed帖子大集合】


一个基础的 LCD显示测试, 原程序基于NXP LPC1768\'s
SPI 接口显示点阵,字符,数字基于 Nokia 5110 ,Nokia 3310 LCD
其控制器为 PCD8544



//平台nucleo 070r+mbed+Nokia5110 SPI屏幕
//
/*1. RST ——复位
2. CE—— 片选
3. DC—— 数据/指令选择
4. DIN —— 串行数据线
5. CLK —— 串行时钟线
6. VCC —— 电源输入(3.3v和5v均可,经过实验验证,没有问题)
7. BL——背光控制端
8. GND —— 地线

接口为串行SPI接口
*/
#include "mbed.h"
#include "N5110.h"
//      VCC,SCE,RST,D/C,MOSI,SCLK,LED
N5110 lcd(D8,D9,D10,D11,D12,D13,D14);
//N5110 lcd VCC,SCE,RST,D/C,MOSI,SCLK,LED:p7,p8,p9,p10,p11,p13,p21
//原程序基于xbed LPC1768      
// Can also power (VCC) directly from VOUT (3.3 V) -
// Can give better performance due to current limitation from GPIO pin

int main()
{
    // first need to initialise display
    lcd.init();

    while(1) {

      // these are default settings so not strictly needed
      lcd.normalMode();      // normal colour mode
      lcd.setBrightness(0.5); // put LED backlight on 50%

      // can directly print strings at specified co-ordinates
      lcd.printString("Hello, World!",0,0);

      char buffer;// each character is 6 pixels wide, screen is 84 pixels (84/6 = 14)
      // so can display a string of a maximum 14 characters in length
      // or create formatted strings - ensure they aren't more than 14 characters long
      int temperature = 27;
      int length = sprintf(buffer,"T = %2d C",temperature); // print formatted data to buffer
      // it is important the format specifier ensures the length will fit in the buffer
      if (length <= 14)// if string will fit on display
            lcd.printString(buffer,0,1);         // display on screen

      float pressure = 1012.3;// same idea with floats
      length = sprintf(buffer,"P = %.2f mb",pressure);
      if (length <= 14)
            lcd.printString(buffer,0,2);

      // can also print individual characters at specified place
      lcd.printChar('X',5,3);

      // draw a line across the display at y = 40 pixels (origin top-left)
      for (int i = 0; i < WIDTH; i++) {
            lcd.setPixel(i,40);
      }
      // need to refresh display after setting pixels
      lcd.refresh();

      // can also check status of pixels using getPixel(x,y)

      wait(5.0);
      lcd.clear();            // clear display
      lcd.inverseMode();      // invert colours
      lcd.setBrightness(1.0); // put LED backlight on full

      float array;

      for (int i = 0; i < 84; i++) {
            array = 0.5 + 0.5*sin(i*2*3.14/84);
      }

      // can also plot graphs - 84 elements only
      // values must be in range 0.0 - 1.0
      lcd.plotArray(array);
      wait(5.0);
      lcd.clear();
      lcd.normalMode();      // normal colour mode back
      lcd.setBrightness(0.5); // put LED backlight on 50%

      // example of drawing lines
      for (int x = 0; x < WIDTH ; x+=10) {
            // x0,y0,x1,y1,type 0-white,1-black,2-dotted
            lcd.drawLine(0,0,x,HEIGHT,2);
      }
      lcd.refresh();   // need to refresh screen after drawing lines

      wait(5.0);
      lcd.clear();

      // example of how to draw circles
      lcd.drawCircle(WIDTH/2,HEIGHT/2,20,1);// x,y,radius,black fill
      lcd.drawCircle(WIDTH/2,HEIGHT/2,10,2);// x,y,radius,white fill
      lcd.drawCircle(WIDTH/2,HEIGHT/2,30,0);// x,y,radius,transparent with outline
      lcd.refresh();   // need to refresh screen after drawing circles

      wait(5.0);
      lcd.clear();
      // example of how to draw rectangles
      //          origin x,y,width,height,type
      lcd.drawRect(10,10,50,30,1);// filled black rectangle
      lcd.drawRect(15,15,20,10,2);// filled white rectange (no outline)
      lcd.drawRect(2,2,70,40,0);    // transparent, just outline
      lcd.refresh();   // need to refresh screen after drawing rects

      wait(5.0);
      lcd.clear();
    }
}


anywill 发表于 2016-10-30 22:00:59

另一种5110屏幕模块采用SPI接口,模块总共有8个引脚,接法如下:1. RST ====>复位
2. CE====>片选
3. DC====>数据/指令选择
4. DIN ====>串行数据线
5. CLK ====>串行时钟线
6. VCC ====>电源输入(3.3v和5v均可)
7. BL====>背光控制端
8. GND ====>地线

zengyi703-16313 发表于 2016-10-31 08:18:09

谢楼主分享

高二毛 发表于 2016-10-31 08:30:51

感谢楼主分享,非常详细啊。:D

xyx365 发表于 2016-10-31 18:54:58

谢谢分享

zwei99999999 发表于 2016-11-1 08:05:07

谢谢楼主分享:):):)

carmelo 发表于 2018-11-19 16:18:15

谢谢分享啊。
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